3.33+1.91x=+0.842x^2

Solution for 3.33+1.91x=+0.842x^2 equation:

3.33+1.91x=+0.842x^2

We move all terms to the left:

3.33+1.91x-(+0.842x^2)=0

We get rid of parentheses

-0.842x^2+1.91x+3.33=0

a = -0.842; b = 1.91; c = +3.33;
Δ = b2-4ac
Δ = 1.912-4·(-0.842)·3.33
Δ = 14.86354
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.91)-\sqrt{14.86354}}{2*-0.842}=\frac{-1.91-\sqrt{14.86354}}{-1.684}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.91)+\sqrt{14.86354}}{2*-0.842}=\frac{-1.91+\sqrt{14.86354}}{-1.684}
$